document.write( "Question 460962: If the endpoints of a diameter of a circle are (4,3)and (-3,5), what is the equation of the circle?
\n" ); document.write( "This is my answer is this right, if not what is?
\n" ); document.write( "Answer
\n" ); document.write( "(5-3)^2+(-3-4)^2
\n" ); document.write( "=2^2+(-7)^2
\n" ); document.write( "=4+49
\n" ); document.write( "=53
\n" ); document.write( " radius=53/2
\n" ); document.write( "midpoint : (1/2, 4)
\n" ); document.write( " equation of the circle=(x-1/2)^2+(y-4)^2=53/4
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Algebra.Com's Answer #316195 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The radius is actually \"r=sqrt%2853%29%2F2\", which will make \"r%5E2=53%2F4\". You forgot to take the square root of 53 in the last step.\r
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\n" ); document.write( "\n" ); document.write( "Anyways, the equation you have is the correct one nonetheless. Good job.
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