document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460962>Question 460962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the endpoints of a diameter of a circle are (4,3)and (-3,5), what is the equation of the circle?<BR>\n" );
document.write( "This is my answer is this right, if not what is?<BR>\n" );
document.write( "Answer<BR>\n" );
document.write( "(5-3)^2+(-3-4)^2 <BR>\n" );
document.write( "=2^2+(-7)^2<BR>\n" );
document.write( "=4+49<BR>\n" );
document.write( "=53<BR>\n" );
document.write( " radius=53/2 <BR>\n" );
document.write( "midpoint : (1/2, 4) <BR>\n" );
document.write( " equation of the circle=(x-1/2)^2+(y-4)^2=53/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316195 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius is actually <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=sqrt%2853%29%2F2 ALIGN=MIDDLE  ALT=\"r=sqrt%2853%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which will make <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2=53%2F4 ALIGN=MIDDLE  ALT=\"r%5E2=53%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >. You forgot to take the square root of 53 in the last step.\r<BR>\n" );
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document.write( "Anyways, the equation you have is the correct one nonetheless. Good job. </SPAN>\n" );
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