document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460980>Question 460980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help please.\r<BR>\n" );
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document.write( "A carpenter is building a rectangular room with a fixed perimeter of 160ft. What dimensions would yield the maximum area. What is the maximum area?<BR>\n" );
document.write( "The length that would yield the maximum area is ___________feet, the width is___<BR>\n" );
document.write( "The maximum area is ______sq feet\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316185 by </B><A HREF=/tutors/aboutme.mpl?userid=JimboP1977><B>JimboP1977(311)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimboP1977><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimboP1977><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+2y=160\r<BR>\n" );
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document.write( "160-2x = 2y<BR>\n" );
document.write( "80-x = y\r<BR>\n" );
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document.write( "xy=A\r<BR>\n" );
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document.write( "x(80-x)=A<BR>\n" );
document.write( "80x-x^2=A\r<BR>\n" );
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document.write( "Find gradient when zero ie the peak.\r<BR>\n" );
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document.write( "80-2x=0\r<BR>\n" );
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document.write( "x=80/2<BR>\n" );
document.write( "x=40\r<BR>\n" );
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document.write( "So maximum area is 80*40-40^2 = 1600 square feet.\r<BR>\n" );
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document.write( "Width is 1600/40 = 40\r<BR>\n" );
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