document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460946>Question 460946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of digits of a two digit number is 15.if the number form by reversing the digits is less than the original number by 27.find the original number.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316159 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "digits are x and (15-x).\r<BR>\n" );
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document.write( "Original number is 10*(15-x)+x , after reversing it is 10*x+(15-x).\r<BR>\n" );
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document.write( "10x + 15-x = 150 -10x + x -27\r<BR>\n" );
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document.write( "=> 18x = 108 \r<BR>\n" );
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document.write( "=> x = 108/18 = 6\r<BR>\n" );
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document.write( "other digit = 15-6 = 9\r<BR>\n" );
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document.write( "so, original number is 96.<BR>\n" );
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