document.write( "Question 460930: Please help me on this problem...I know how to go to the edit screen and insert the data in the calculator but im not sure what to do next.. I would like to know how to do it on paper also.\r
\n" ); document.write( "\n" ); document.write( "For the data below:\r
\n" ); document.write( "\n" ); document.write( "year, x / number of electroically filed tax returns, y(in millions)
\n" ); document.write( "1995, 0 / 11.807
\n" ); document.write( "1997, 2 / 19.136
\n" ); document.write( "1999, 4 / 29.349
\n" ); document.write( "2001, 6 / 40.245
\n" ); document.write( "2003, 8 / 52.945
\n" ); document.write( "2005, 10 / 68.476\r
\n" ); document.write( "\n" ); document.write( "a)find a linear model using the years 0 and 4
\n" ); document.write( "b)find a linear model using the graphing calculator.
\n" ); document.write( "c)what is the correlation coefficient?
\n" ); document.write( "d)use your model to predict the numbers for 2010.
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Algebra.Com's Answer #316158 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
a)find a linear model using the years 0 and 4
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document.write( "Find the equation of a line through the points\r\n" );
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document.write( "(0,11.807) and (4,29.349)\r\n" );
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document.write( "m = \"%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29=%2829.349-11.807%29%2F%284-0%29+=+4.3855\"\r\n" );
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document.write( "then use \r\n" );
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document.write( "y - y1 = m(x - x1)\r\n" );
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document.write( "y - 11.807 = 4.3855(x - 0)\r\n" );
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document.write( "y - 11.807 = 4.3855x\r\n" );
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document.write( "         y = 4.3855x + 11.807\r\n" );
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\n" ); document.write( "b)find a linear model using the graphing calculator.
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\r\n" );
document.write( "press CLEAR\r\n" );
document.write( "press STAT\r\n" );
document.write( "press the right arrow key to highlight CALC\r\n" );
document.write( "press 4\r\n" );
document.write( "You will see \r\n" );
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document.write( "               LinReg(ax+b)\r\n" );
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document.write( "Press ENTER\r\n" );
document.write( "You will see\r\n" );
document.write( "               LinReg \r\n" );
document.write( "                y=ax+b\r\n" );
document.write( "                a=5.6524\r\n" );
document.write( "                b=8.731\r\n" );
document.write( "                rē=.9861609225\r\n" );
document.write( "                r=.9930563541\r\n" );
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document.write( "The equation of the line is y = 5.6524x + 8.731\r\n" );
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\n" ); document.write( "c)what is the correlation coefficient?
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document.write( "That's the value of r, which is r=.9930563541\r\n" );
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\n" ); document.write( "d)use your model to predict the numbers for 2010.
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document.write( "1995, 0 \r\n" );
document.write( "1997, 2\r\n" );
document.write( "1999, 4\r\n" );
document.write( "2001, 6 \r\n" );
document.write( "2003, 8 \r\n" );
document.write( "2005, 10 \r\n" );
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document.write( "Extend this list by 2's:\r\n" );
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document.write( "2007, 12\r\n" );
document.write( "2009, 14\r\n" );
document.write( "2011, 16\r\n" );
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document.write( "Since 2010 is halfway between 2009, 14 and 2011 16,\r\n" );
document.write( "we must have 2010 as 15.\r\n" );
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document.write( "So we substitute 15 for x in the formula:\r\n" );
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document.write( "y = 5.6524x + 8.731\r\n" );
document.write( "y = 5.6524(15) + 8.731\r\n" );
document.write( "y = 93.517\r\n" );
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document.write( "Edwin
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