document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47817>Question 47817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a 2 digit no. is 9, when the digits are reversed the new no. is 27 more than the original no. Find the no.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31615 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a 2 digit no. is 9, when the digits are reversed the new no. is 27 more than the original no. Find the no.<BR>\n" );
document.write( "LET XY BE THE NUMBER...SUM OF DIGITS =X+Y=9.....................I<BR>\n" );
document.write( "ITS VALUE =10X+Y<BR>\n" );
document.write( "WHEN DIGITS ARE REVERSED WE GET YX...ITS VALUE = 10Y+X<BR>\n" );
document.write( "DIFFERENCE BETWEEN THE 2 NUMBERS =27=10Y+X-10X-Y=9Y-9X=9(Y-X)<BR>\n" );
document.write( "Y-X=3.............II<BR>\n" );
document.write( "EQN.I+EQN.II....<BR>\n" );
document.write( "2Y=9+3=12<BR>\n" );
document.write( "Y=12/2=6<BR>\n" );
document.write( "X=9-Y=9-6=3<BR>\n" );
document.write( "THE NUMBER IS 36 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );