document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47818>Question 47818</A>: <I><SPAN STYLE=\"word-break: break-all;\">  SUBSTITUTION METHOD 3X - 3Y = 2    EQUATION 1<BR>\n" );
document.write( "                      X + 2  = 3Y   EQUATION 2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31614 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  SUBSTITUTION METHOD 3X - 3Y = 2 EQUATION 1\r<BR>\n" );
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document.write( "X + 2 = 3Y EQUATION 2<BR>\n" );
document.write( "X=3Y-2<BR>\n" );
document.write( "PUT IN EQN.I<BR>\n" );
document.write( "3(3Y-2)-3Y=2<BR>\n" );
document.write( "9Y-6-3Y=2<BR>\n" );
document.write( "6Y=6+2=8<BR>\n" );
document.write( "Y=8/6=4/3<BR>\n" );
document.write( "X=3*(4/3)-2=4-2=2 </SPAN>\n" );
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