document.write( "Question 460851: a three-digit number satisfies the following conditions: the digits are consecutive whole numbers; the sum of the digits is greater than 10 and less than 20; and the tens digit is ann odd number. what is the number? \n" ); document.write( "
Algebra.Com's Answer #316116 by poliphob3.14(115)![]() ![]() ![]() You can put this solution on YOUR website! Let the tens digit = 2k+1, an odd number, then the hundreds digit is 2k and the units digit 2k+2, where k is a natural number. These digits must satisfy the conditions: 10 < 2k+2k+1+2k+2 <20 Solving these inequalities we get: \n" ); document.write( "10< 6k+3 <20 => 7< 6k <20 => 7/6< k <20/7 These inequalities are equivalent to the inequalities: 1< k <3, since k is a natural number we conclude that k=1, and the digits of our number are: 2k=4; 2k+1=5 and 2k+2=6.\r \n" ); document.write( "\n" ); document.write( "Answer: The number is 456, which satisfy our conditions. \n" ); document.write( " |