document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460778>Question 460778</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bob Dansky and Sandy Spears are at opposite ends of a shopping mall 4780.4 feet apart walking towards each other.  If Barb walks<BR>\n" );
document.write( "1.5 feet per second and Sandy walks 2.2 feet per second, how long will it be before they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316106 by </B><A HREF=/tutors/aboutme.mpl?userid=rwm><B>rwm(914)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rwm><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since they are walking towards each other we can add their speeds together<BR>\n" );
document.write( "1.5 +2.2=3.7<BR>\n" );
document.write( "they need to go 4780.4 feet<BR>\n" );
document.write( "4780.4/3.7 will give us the number of seconds<BR>\n" );
document.write( "1292 seconds<BR>\n" );
document.write( "21.53 minutes<BR>\n" );
document.write( "21 8/15=21min 32 seconds<BR>\n" );
document.write( " </SPAN>\n" );
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