document.write( "Question 460796: A pile of pennies, dimes, and half dollars (100 coins in all) is worth $5. How many dimes are in the pile? \n" ); document.write( "
Algebra.Com's Answer #316090 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"p\" = number of pennies
\n" ); document.write( "Let \"d\" = number of dimes
\n" ); document.write( "Let \"h\" = number of half dollars
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+p+%2B+d+%2B+h+=+100+\"
\n" ); document.write( "(2) \"+1%2Ap+%2B+10d+%2B+50h+=+500+\"
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\n" ); document.write( "There are 2 equations and 3 unknowns, so
\n" ); document.write( "it is not directly solvable, but I can make
\n" ); document.write( "some logical conclusions.
\n" ); document.write( "(a)
\n" ); document.write( "The number of pennies is even and also
\n" ); document.write( "a multiple of \"+10+\", otherwise, you
\n" ); document.write( "can't end up with a total of \"+500+\".
\n" ); document.write( "(b)
\n" ); document.write( "You can't have \"+50+\" dimes, since that
\n" ); document.write( "equals \"+500+\".
\n" ); document.write( "(c)
\n" ); document.write( "The most dimes you could possibly have is
\n" ); document.write( "\"+40+\", and then you have:
\n" ); document.write( "\"+50+\" pennies = $.50
\n" ); document.write( "\"+40+\" dimes = $4.00
\n" ); document.write( "\"+1+\" half dollar = $.50
\n" ); document.write( "but then you only have \"+91+\" coins
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\n" ); document.write( "Suppose you have 1 less dime. You have:
\n" ); document.write( "\"+60+\" pennies = $.60
\n" ); document.write( "\"+39+\" dimes = $3.90
\n" ); document.write( "\"+1+\" half dollar = $.50
\n" ); document.write( "That adds up to \"+100+\" coins and
\n" ); document.write( "must be the answer.\r
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