document.write( "Question 454172: how do i evaluate\r
\n" ); document.write( "\n" ); document.write( "log(base 3)1/3 + log(base 5) square root 5
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Algebra.Com's Answer #316084 by lwsshak3(11628)\"\" \"About 
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how do i evaluate
\n" ); document.write( "log(base 3)1/3 + log(base 5) square root 5
\n" ); document.write( "..
\n" ); document.write( "log3(1/3)+log5(5^1/2)
\n" ); document.write( "convert to exponential form:(base raised to log of number(x)=number
\n" ); document.write( "3^x=1/3
\n" ); document.write( "3^-1=1/3
\n" ); document.write( "x=-1(log of 1/3, base3)
\n" ); document.write( "check:3^x=3^-1=1/3
\n" ); document.write( "..
\n" ); document.write( "log5(5^1/2)
\n" ); document.write( "5^x=5^1/2
\n" ); document.write( "5^1/2=5^1/2
\n" ); document.write( "x=1/2(log of 5^1/2, base5)
\n" ); document.write( "check:
\n" ); document.write( "5^x=5^1/2
\n" ); document.write( "..
\n" ); document.write( "ans:
\n" ); document.write( "log3(1/3)+log5(5^1/2)
\n" ); document.write( "-1+1/2=-1/2
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