document.write( "Question 458771: solve for x:
\n" ); document.write( "log5x + log25x=2.5 \n" ); document.write( "

Algebra.Com's Answer #316083 by lwsshak3(11628) $\"\"$ $\"About$

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solve for x:
\n" ); document.write( "log5x + log25x=2.5
\n" ); document.write( "..
\n" ); document.write( "log5x + log25x=2.5
\n" ); document.write( "place under single log
\n" ); document.write( "log(5x*25x)=2.5
\n" ); document.write( "log(125x^2)=2.5
\n" ); document.write( "convert to exponential form:(base(10) raised to log of number(2.5)=number(125x^2)
\n" ); document.write( "10^2.5=125x^2=316.2278
\n" ); document.write( "x^2=316.2278/125=2.5298
\n" ); document.write( "x=ą√(2.5298)
\n" ); document.write( "x=1.59
\n" ); document.write( "or
\n" ); document.write( "x=-1.59 (reject, x>0)
\n" ); document.write( "Check:
\n" ); document.write( "log(5x)+log(25x)=.9004+1.59=2.49+ \n" ); document.write( "

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