document.write( "Question 460767: A doctor says that less than 25% of US adults chew tobacco. In a random sample of 170 US adults, 18.5% say they chew tobacco. At alpha = .05, is there enough evidence to reject the doctor's claim? \r
\n" ); document.write( "\n" ); document.write( "Since I don't have a standard deviation, do I use t-distribution? Or do I use binomial distribution and find it by square root of npq?
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Algebra.Com's Answer #316053 by stanbon(75887)\"\" \"About 
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A doctor says that less than 25% of US adults chew tobacco.
\n" ); document.write( "In a random sample of 170 US adults, 18.5% say they chew tobacco.
\n" ); document.write( "At alpha = .05, is there enough evidence to reject the doctor's claim?
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\n" ); document.write( "Since I don't have a standard deviation, do I use t-distribution? Or do I use --binomial distribution and find it by square root of npq?
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\n" ); document.write( "It is a proportion test so you use the z-distribution.
\n" ); document.write( "The standard deviation is sqrt[pq/n]. You have all
\n" ); document.write( "the information you need.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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