document.write( "Question 460743: For the 4th of July picnic,Teresa is preparing a selection of meat dishes. She is cooking 6 1/2 pounds of hot dogs,5 3/4 pounds of hamburger, and4 5/8pounds of cold cuts. Assuming that each person will eat 5/8 pounds of meat during the day long picnic,how many people will Teresa's meat dishes serve? \n" ); document.write( "
Algebra.Com's Answer #316045 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! For the 4th of July picnic,Teresa is preparing a selection of meat dishes. \n" ); document.write( "She is cooking 6 1/2 pounds of hot dogs,5 3/4 pounds of hamburger, \n" ); document.write( "and 4 5/8 pounds of cold cuts. Assuming that each person will eat 5/8 pounds of meat during the day long picnic, how many people will Teresa's meat dishes serve? \n" ); document.write( "-------------- \n" ); document.write( "Total Weight: 13/2 + 23/4 37/8 \n" ); document.write( "lcd = 8 \n" ); document.write( "= [4*13 + 2*34 + 37]/8 \n" ); document.write( "= 157/8 lbs \n" ); document.write( "---- \n" ); document.write( "# of people the meat can serve: \n" ); document.write( "(157/8)/(5/8) \n" ); document.write( "= 157/5 \n" ); document.write( "= 31.4 \n" ); document.write( "= 31 when rounded down \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |