document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460728>Question 460728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bag contains 20 batteries, of which six are defective. Selecting two at random, without replacement, determine the probability that none of the batteries you select are good.<BR>\n" );
document.write( ">3/5<BR>\n" );
document.write( ">3/10<BR>\n" );
document.write( ">3/38<BR>\n" );
document.write( ">9/100<BR>\n" );
document.write( "please show me how you get the answer?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316038 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(2 Defective) = P(Defective AND defective)\r<BR>\n" );
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document.write( "P(2 Defective) = P(Defective) * P(Defective)\r<BR>\n" );
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document.write( "P(2 Defective) = (6/20)*(5/19)\r<BR>\n" );
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document.write( "P(2 Defective) = (6*5)/(20*19)\r<BR>\n" );
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document.write( "P(2 Defective) = 30/380\r<BR>\n" );
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document.write( "P(2 Defective) = 3/38\r<BR>\n" );
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document.write( "So the probability that both are defective is 3/38, which means that the answer is choice C)<BR>\n" );
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