document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6004>Question 6004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the slope of a line that is parallel to and slope that is perpendicular to the following line:  y=-3x\r<BR>\n" );
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document.write( "Thanks  Caroline </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3160 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In the equation of a line in the form y=mx+b, the coefficient of x is the slope of the line.  The slope of this line <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-3x+ ALIGN=MIDDLE  ALT=\"y=-3x+\"   DISABLED_style= \"max-width:90%; height:auto;\" > is therefore the coefficient of x, which is -3.  A line parallel to this line is going in the same direction, so it also has a slope of m= -3.  \r<BR>\n" );
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document.write( "A line that is perpendicular to a given line has a slope that is the NEGATIVE RECIPROCAL of the slope of the given line.  Therefore, the slope of a line perpendicular to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-3x ALIGN=MIDDLE  ALT=\"y+=+-3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > must have a slope that is the opposite sign AND the reciprocal of m = -3, which is  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+m+=+1%2F3 ALIGN=MIDDLE  ALT=\"+m+=+1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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