document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47791>Question 47791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equation in standard form:<BR>\n" );
document.write( "xsquared+ysquared-6x-4y+13=36<BR>\n" );
document.write( "sorry that i cant find a small 2 for the squared.  i hope this makes sense.  please help me figure this out.  thanks so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31597 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31597\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+y^2-6x-4y+13=36<BR>\n" );
document.write( "Complete the square on the x terms and on the y terms separately to get:\r<BR>\n" );
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document.write( "x^2-6x+9 +y^2-4y+4 =36-13+9+4\r<BR>\n" );
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document.write( "(x-3)^2 + (y-2)^2 = 36\r<BR>\n" );
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document.write( "This is the equation for a circle with center<BR>\n" );
document.write( "at (3,2) and radius of 6\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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