document.write( "Question 47791: write the equation in standard form:
\n" ); document.write( "xsquared+ysquared-6x-4y+13=36
\n" ); document.write( "sorry that i cant find a small 2 for the squared. i hope this makes sense. please help me figure this out. thanks so much!
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Algebra.Com's Answer #31596 by pizza(14)\"\" \"About 
You can put this solution on YOUR website!
The first thing that needs clarification is the term 'standard form'.
\n" ); document.write( "The equation happens to be in standard form already.
\n" ); document.write( "However, I deduce from the title, that by standard form, you want to rearrange the equation such that it is evidently a conic section. The standard form of a conic section is as follows:
\n" ); document.write( "\"+%28%28x-a%29%5E2%29%2Fc+%2B+%28%28y-b%29%5E2%29%2Fd+=+r%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "This implies that you have to do some factorisation.
\n" ); document.write( "I assume you are familiar with completing the square.
\n" ); document.write( "If you are, then you will know that
\n" ); document.write( "\"+x%5E2+-+6x+=+%28x-3%29%5E2+-+9+\"
\n" ); document.write( "And
\n" ); document.write( "\"+y%5E2+-+4x+=+%28y-2%29%5E2+-+4+\"
\n" ); document.write( "Then putting this into the original equation, we have
\n" ); document.write( "\"+%28x-3%29%5E2+%2B+%28y-2%29%5E2+=+36+=+6%5E2+\"
\n" ); document.write( "which is in standard form.
\n" ); document.write( "Hooray!\r
\n" ); document.write( "\n" ); document.write( "When c = d = 1, we have an equation for a circle, otherwise it is an equation of an ellipse. Circles and ellipses are conic sections.\r
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