document.write( "Question 460555: The average of the squares of seven consecutives integers is 53. The average of these integers is? \n" ); document.write( "
Algebra.Com's Answer #315927 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Let x-3, x-2, ..., x+3 be the seven integers, with\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we were to expand this all out, we would see that all the x terms would disappear (-6x on the left term cancels out 6x on the right, and so on). We are left with\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The average of the integers x-3, x-2, ..., x+3 is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the average of the original seven integers is either 7 or -7. \n" ); document.write( " |