document.write( "Question 460555: The average of the squares of seven consecutives integers is 53. The average of these integers is? \n" ); document.write( "
Algebra.Com's Answer #315927 by richard1234(7193)\"\" \"About 
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Let x-3, x-2, ..., x+3 be the seven integers, with\r
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\n" ); document.write( "\n" ); document.write( "If we were to expand this all out, we would see that all the x terms would disappear (-6x on the left term cancels out 6x on the right, and so on). We are left with\r
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\n" ); document.write( "\n" ); document.write( "The average of the integers x-3, x-2, ..., x+3 is\r
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\n" ); document.write( "\n" ); document.write( " Again, the constant terms cancel, leaving\r
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\n" ); document.write( "\n" ); document.write( "So the average of the original seven integers is either 7 or -7.
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