document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460571>Question 460571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A factory needs two raw materials, say E and F. The probability of not having an adequate supply of material E is 0.06, whereas the probability of not having an adequate supply of material F is 0.04. A study shows that the probabilty of a sgortage of both E and F is 0.02. What is the probability of the factory being short of either material E or F? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315904 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The probability of not having an adequate supply of material E is 0.06, whereas the probability of not having an adequate supply of material F is 0.04.<BR>\n" );
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document.write( "P(E') = 0.06 ; P(E) = 0.94<BR>\n" );
document.write( "P(F') = 0.04 ; P(F) = 0.96<BR>\n" );
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document.write( " A study shows that the probabilty of a shortage of both E and F is 0.02.<BR>\n" );
document.write( "P(E' and F') = 0.02<BR>\n" );
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document.write( "What is the probability of the factory being short of either material E or F?<BR>\n" );
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document.write( "P(E' or F') = P(E')+P(F')-P(E' and F') = 0.06+0.04-0.02 = 0.08<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
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