document.write( "Question 460511: 5x+20y=115, 8y+4x=52 \n" ); document.write( "
Algebra.Com's Answer #315856 by Alan3354(69443)\"\" \"About 
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5x+20y=115, 8y+4x=52
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\n" ); document.write( "5x+20y=115 --> x + 4y = 23 divided by 5
\n" ); document.write( "4x+ 8y=52 --> x + 2y = 13 divided by 4
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\n" ); document.write( "x + 4y = 23
\n" ); document.write( "x + 2y = 13
\n" ); document.write( "----------- Subtract
\n" ); document.write( "2y = 10
\n" ); document.write( "y = 5
\n" ); document.write( "--------
\n" ); document.write( "x + 2y = 13
\n" ); document.write( "x + 2*5 = 13
\n" ); document.write( "x = 3\r
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