document.write( "Question 460435: A doctor says that greater than 20% of US adults chew tobacco. In a random sample of 170 US adults, 15.5% say they chew tobacco. At alpha = .05, is there enough evidence to reject the doctor's claim?\r
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document.write( "null: > or equal to .20
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document.write( "alternative: < .20
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document.write( "Left tailed test \n" );
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Algebra.Com's Answer #315851 by edjones(8007)![]() ![]() You can put this solution on YOUR website! H[o]:>.20 \n" ); document.write( "n=170, P=.155 Q=.845 \n" ); document.write( "z=(.155-.200)/sqrt((.155*.845)/170)=-.045/.028=-1.62 \n" ); document.write( "Since -1.62>-1.64 (the low bound of .05), we cannot reject the null hypothesis. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |