document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460508>Question 460508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a logarithm problem, I don't understand\r<BR>\n" );
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document.write( "Use log b(7)= 1.946 and/or log 6(5)=1.069 to find the logarithm of log b(1/7)\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315850 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use log b(7)= 1.946 and/or log 6(5)=1.069 to find the logarithm of log b(1/7)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Starting with:<BR>\n" );
document.write( "log b(1/7)<BR>\n" );
document.write( "we can rewrite as:<BR>\n" );
document.write( "log b(1/7^1)<BR>\n" );
document.write( "log b(7^(-1))<BR>\n" );
document.write( "(-1)log b(7)<BR>\n" );
document.write( "Now we can substitute in the given value of log b(7):<BR>\n" );
document.write( "(-1)(1.946)<BR>\n" );
document.write( "-1.946\r<BR>\n" );
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document.write( " </SPAN>\n" );
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