document.write( "Question 458934: log(base2)8 + 2log(base2)x = log(base2)(14x-3) \n" ); document.write( "
Algebra.Com's Answer #315824 by lwsshak3(11628)\"\" \"About 
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log(base2)8 + 2log(base2)x = log(base2)(14x-3)
\n" ); document.write( "..
\n" ); document.write( "log2(8)+2log2(x)=log2(14x-3)
\n" ); document.write( "log2(8)+2log2(x)-log2(14x-3)=0
\n" ); document.write( "log2(8x^2/14x-3)=0
\n" ); document.write( "convert to exponential form: (base(2) raised to log of number(0)=number(8x^2/14x-3)
\n" ); document.write( "2^0=(8x^2/14x-3)=1
\n" ); document.write( "8x^2=14x-3
\n" ); document.write( "8x^2-14x+3=0
\n" ); document.write( "solve by quadratic formula
\n" ); document.write( "a=8, b=-14, c=3
\n" ); document.write( "x=[-(-14)ħsqrt(-14)^2-4*8*3]2*8
\n" ); document.write( "x=[14ħsqrt(196-96]/16
\n" ); document.write( "x=(14ħ√100)/16=14ħ10/16
\n" ); document.write( "x=24/16=1.5
\n" ); document.write( "or
\n" ); document.write( "x=4/16=.25 \n" ); document.write( "
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