document.write( "Question 459833: The width of a rectangle is three fourths of the length. The perimeter of the rectangle becomes 50 cm when the length and the width are each increased by 2 cm. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #315814 by simranb(63)\"\" \"About 
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Perimeter=2(l+b)
\n" ); document.write( "Let the length be x
\n" ); document.write( "then width=3/4x
\n" ); document.write( "when length and width are increased by 2 the the perimeter=50
\n" ); document.write( "2(x+2+3/4x+2)=50
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Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:

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\n" ); document.write( " YOUR ANSWER\n" ); document.write( "


\n" ); document.write( "Sorry, this expression cannot be simplified.

Universal Simplifier and Solver

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Done!

\n" ); document.write( "\n" ); document.write( "then length=12
\n" ); document.write( " Width=3/4 of x
\n" ); document.write( " = 3/4 * 12
\n" ); document.write( " = 9
\n" ); document.write( "Hope this helps! \n" ); document.write( "
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