document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460436>Question 460436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sam has 5 rings each weighing 18g, made of an alloy of 10% silver and 90% gold.  He decides to melt down the rings and add enough silver to reduce the gold content to 75%.   How much silver should he add? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315812 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s=.1*(18)=1.8<BR>\n" );
document.write( "g=.9*(18)=16.2<BR>\n" );
document.write( "from view of silver<BR>\n" );
document.write( "1.8+x/(18+x)=.25<BR>\n" );
document.write( "x=3.6<BR>\n" );
document.write( "add 3.6 g of silver\r<BR>\n" );
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document.write( "from view of gold<BR>\n" );
document.write( "16.2/(18+x)=.75<BR>\n" );
document.write( "x=3.6<BR>\n" );
document.write( "add 3.6 g of silver\r<BR>\n" );
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document.write( " </SPAN>\n" );
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