document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47785>Question 47785</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618306161/algebrahomeworkh>Intermediate Algebra with Applications</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> solve: square root of 2x+5 - square root of 3x-2 = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31579 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31579\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(2x+5)-sqrt(3x-2)=1 or squaring all terms we get 2x+5-3x+2=1 or\r<BR>\n" );
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document.write( "-x=-6 or x=6\r<BR>\n" );
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document.write( "proof sqrt (2*6+5)-sqrt(3*6-2=1 or sqrt(12+5)-sqrt(3*6-2)=1 or <BR>\n" );
document.write( "sqrt17-sqrt16=1 squaring all terms we get 17-16=1 or 1=1 </SPAN>\n" );
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