document.write( "Question 460211: what is the equation for the line that contains the point (6,-10) and is perpendicular to the line y=-8+x \n" ); document.write( "
Algebra.Com's Answer #315771 by ankor@dixie-net.com(22740)\"\" \"About 
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what is the equation for the line that contains the point (6,-10) and is perpendicular to the line y=-8+x
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\n" ); document.write( "Write in the slope/intercept form y = mx+b
\n" ); document.write( "y = x - 8
\n" ); document.write( "the slope is +1
\n" ); document.write( "then the slope of the perpendicular line = -1
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\n" ); document.write( "Use the point/slope form y - y1 = m(x - x1)
\n" ); document.write( "in this equation m=-1, x1=6, y1=-10
\n" ); document.write( "y - (-10) = -1(x - 6)
\n" ); document.write( "y + 10 = -x + 6
\n" ); document.write( "y = -x + 6 - 10
\n" ); document.write( "y = -x - 4, is the equation \n" ); document.write( "
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