document.write( "Question 460352: Can someone help me, I am having trouble with this word problem\r
\n" ); document.write( "\n" ); document.write( "In 1990, the life expectancy of males in a certain country was 68.4 years 71.7 years. Let E represent the life expectancy in year t represent the number of years since 1990. The linear equarion E(t) that fits that data is E (t)= __+__
\n" ); document.write( "round to the nearest tenth/\r
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "
Algebra.Com's Answer #315738 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In 1990, the life expectancy of males in a certain country was 68.4 years and 71.7 years in 1996. Let E represent the life expectancy in year t represent the number of years since 1990. The linear equarion E(t) that fits that data is E (t)= __+__
\n" ); document.write( "round to the nearest tenth/
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\n" ); document.write( "You have two points: (0,68.4) and (6,71.7)
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\n" ); document.write( "slope = (71.7-68.4)/(6-0) = 0.55
\n" ); document.write( "Note: (0,68.4) gives the y-intercept.
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\n" ); document.write( "Equation: E(t) = 0.55t + 68.4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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