document.write( "Question 460256: Please help with this question...I cant figure it out...thanks!\r
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document.write( "Suppose $5000 is in invested at interest rate k, compounded continuously, and grows to 6954.84 in 6 yr.
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document.write( "a)Find the interest rate.
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document.write( "b)Find the exponential growth function.
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document.write( "c)Find the balance after 10 yr.
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document.write( "d)Find the doubling time. \n" );
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Algebra.Com's Answer #315732 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Suppose $5000 is in invested at interest rate k, compounded continuously, and grows to 6954.84 in 6 yr. \n" ); document.write( "a)Find the interest rate. \n" ); document.write( "Think: A = Pe^(kt) \n" ); document.write( "plug in given values to find r: \n" ); document.write( "6954.84 = 5000e^(6k) \n" ); document.write( "1.390968 = e^(6k) \n" ); document.write( "ln(1.390968) = 6k \n" ); document.write( "ln(1.390968)/6 = k \n" ); document.write( "0.055 = k \n" ); document.write( "or \n" ); document.write( "5.5% = k \n" ); document.write( ". \n" ); document.write( "b)Find the exponential growth function. \n" ); document.write( "A = Pe^(kt) \n" ); document.write( "A = 5000e^(0.055t) \n" ); document.write( ". \n" ); document.write( "c)Find the balance after 10 yr. \n" ); document.write( "Set t to 10 and solve for A: \n" ); document.write( "A = 5000e^(0.055t) \n" ); document.write( "A = 5000e^(0.055*10) \n" ); document.write( "A = 5000e^(0.55) \n" ); document.write( "A = $8666.27 \n" ); document.write( ". \n" ); document.write( "d)Find the doubling time. \n" ); document.write( "A = 5000e^(0.055t) \n" ); document.write( "Set A to 10000 and solve for t: \n" ); document.write( "10000 = 5000e^(0.055t) \n" ); document.write( "2 = e^(0.055t) \n" ); document.write( "ln(2) = 0.055t \n" ); document.write( "ln(2)/0.055 = t \n" ); document.write( "12.6 years = t \n" ); document.write( " \n" ); document.write( " |