document.write( "Question 460307: \"root%285%2C+%288x%5E3%29%2F%28y%5E4%29%29%2Aroot%285%2C+%284x%5E4%29%2F%28y%5E2%29%29\"
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Algebra.Com's Answer #315722 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\"root%285%2C+%288x%5E3%29%2F%28y%5E4%29%29%2Aroot%285%2C+%284x%5E4%29%2F%28y%5E2%29%29\"
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document.write( "Multiply under the radicals and get\r\n" );
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document.write( "\"root%285%2C+%2832x%5E7%29%2F%28y%5E6%29%29\"\r\n" );
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document.write( "Break it into the quotient of two fifth roots:\r\n" );
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document.write( "\"root%285%2C+32x%5E7%29%2Froot%285%2Cy%5E6%29\"\r\n" );
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document.write( "The power of y in the denominator must be a\r\n" );
document.write( "multiple of 5, so it needs to be multiplied by\r\n" );
document.write( "y4 so that it will become y10.\r\n" );
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document.write( "So we multiply the entire fraction by \"root%285%2Cy%5E4%29%2Froot%285%2Cy%5E4%29\"\r\n" );
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document.write( "We multiply under the radicals:\r\n" );
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document.write( "\"expr%28root%285%2C+32x%5E7y%5E4%29%2Froot%285%2Cy%5E10%29%29\"\r\n" );
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document.write( "The denominator is simplified by dividing the exponent 10\r\n" );
document.write( "by the index of the root 5, getting exponent 2, and \r\n" );
document.write( "eliminating the radical,  so we have\r\n" );
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document.write( "\"expr%28root%285%2C+32x%5E7y%5E4%29%2Fy%5E2%29\"\r\n" );
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document.write( "Now we will simplify the numerator.\r\n" );
document.write( "Write 32 as 25\r\n" );
document.write( "Write x7 as x5x2\r\n" );
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document.write( "\"expr%28root%285%2C+2%5E5x%5E5x%5E2y%5E4%29%2Fy%5E2%29\"\r\n" );
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document.write( "Finally you can take the two fifth powers out\r\n" );
document.write( "of the fifth root and have 2x in front of the\r\n" );
document.write( "radical:\r\n" );
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document.write( "\"%282x%2Aroot%285%2C+x%5E2y%5E4%29%29%2Fy%5E2\"\r\n" );
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document.write( "Edwin
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