document.write( "Question 460215: How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution? \n" ); document.write( "
Algebra.Com's Answer #315715 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .50x+.35*10=.40(10+x) \n" ); document.write( ".50x+3.5=4+.40x \n" ); document.write( ".50x-.40x=4-3.5 \n" ); document.write( ".10x=.5 \n" ); document.write( "x=.5/.10 \n" ); document.write( "x=5 gallons of 50% are required, \n" ); document.write( "Proof: \n" ); document.write( ".50*5+.35*10=.40(10+5) \n" ); document.write( "2.5+3.5=.4*15 \n" ); document.write( "6=6 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |