document.write( "Question 460215: How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution? \n" ); document.write( "
Algebra.Com's Answer #315715 by checkley79(3341)\"\" \"About 
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.50x+.35*10=.40(10+x)
\n" ); document.write( ".50x+3.5=4+.40x
\n" ); document.write( ".50x-.40x=4-3.5
\n" ); document.write( ".10x=.5
\n" ); document.write( "x=.5/.10
\n" ); document.write( "x=5 gallons of 50% are required,
\n" ); document.write( "Proof:
\n" ); document.write( ".50*5+.35*10=.40(10+5)
\n" ); document.write( "2.5+3.5=.4*15
\n" ); document.write( "6=6
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