document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460264>Question 460264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length L of a spring is given by L = 3/8F + 19, where F is the applied force. What force F will produce a length, L = 34?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315688 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315688\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = (3/8)F + 19<BR>\n" );
document.write( "34=3F/8+19 SUBTRACT 19<BR>\n" );
document.write( "3F/8=34-19 <BR>\n" );
document.write( "3F/8=15 CROSS MULTIPLY<BR>\n" );
document.write( "3F=6*15 <BR>\n" );
document.write( "3F=80 DIVIDE BY 3<BR>\n" );
document.write( "F=80/3 <BR>\n" );
document.write( "F=26.67 ANS. </SPAN>\n" );
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