document.write( "Question 460185: how to solve log(2)8 - 2log(6)3 - log(6)4 = ??\r
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Algebra.Com's Answer #315673 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "log28 - 2log63 - log64\r\n" );
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document.write( "Write 8 as 2³, and write 2log63 as log63²\r\n" );
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document.write( "log22³ - log63² - log64\r\n" );
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document.write( "Write log22³ as 3log22\r\n" );
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document.write( "3log22 - log63² - log64\r\n" );
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document.write( "Write 3log22 as 3(1) or just 3\r\n" );
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document.write( "3 - log63² - log64\r\n" );
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document.write( "Factor -1 out of the last two terms:\r\n" );
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document.write( "3 -1(log63² + log64)\r\n" );
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document.write( "Write 3² as 9\r\n" );
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document.write( "3 -1(log69 + log64)\r\n" );
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document.write( "Write the sum of logs in parentheses as the log of \r\n" );
document.write( "a product\r\n" );
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document.write( "3 - 1(log69*4)\r\n" );
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document.write( "Write 9*4 as 36\r\n" );
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document.write( "3 - 1(log636)\r\n" );
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document.write( "Write 36 as 6²\r\n" );
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document.write( "3 - 1(log66²)\r\n" );
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document.write( "Write the log66² as 2log66\r\n" );
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document.write( "3 - 1(2log66)\r\n" );
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document.write( "Write log66 as 1\r\n" );
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document.write( "3 - 1(2*1)\r\n" );
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document.write( "3 - 2\r\n" );
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document.write( "1\r\n" );
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document.write( "Edwin
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