document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460235>Question 460235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the maximum possible area of a rectangle with a perimeter of 14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315669 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  what is the maximum possible area of a rectangle with a perimeter of 14<BR>\n" );
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document.write( "Perimeter = 2(L + W) = 14<BR>\n" );
document.write( "L+W = 7<BR>\n" );
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document.write( "L = 7-W<BR>\n" );
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document.write( "Area = LW<BR>\n" );
document.write( "Solve: (7-W)W = maximum Area<BR>\n" );
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document.write( "A = 7W-W^2<BR>\n" );
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document.write( "Maximum A occurs when W = -b/(2a) = -7/(2*-1) = 3.5<BR>\n" );
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document.write( "Max Area = 3.5*3.5 = 12.25 sq. units<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== </SPAN>\n" );
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