document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47767>Question 47767</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please help solve for x and check work.\r<BR>\n" );
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document.write( "–3(x + 1) = 2(x – 8) + 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31563 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> –3(x + 1) = 2(x – 8) + 3\r<BR>\n" );
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document.write( "-3x-3 = 2x-16+3<BR>\n" );
document.write( "Get the x terms on one side the the number terms on the other, as follows:\r<BR>\n" );
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document.write( "5x=-3+13<BR>\n" );
document.write( "5x=10<BR>\n" );
document.write( "x=2<BR>\n" );
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document.write( "Checking the answer:<BR>\n" );
document.write( "-3(2+1) = 2(2-8)+3<BR>\n" );
document.write( "-3(3) = 2(-6)+3<BR>\n" );
document.write( "-9 = -12+3<BR>\n" );
document.write( "-9= -9<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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