document.write( "Question 460142: Five times the smallest of three consecutive odd integers is nine more than four times the second integer. Find the third integer. \n" ); document.write( "
Algebra.Com's Answer #315625 by JimboP1977(311)\"\" \"About 
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let x be the smallest of the three consecutive integer\r
\n" ); document.write( "\n" ); document.write( "5x - 9 = 4(x+2)
\n" ); document.write( "5x-9 = 4x+8
\n" ); document.write( "5x-17 = 4x
\n" ); document.write( "-17 = -x
\n" ); document.write( "17 = x\r
\n" ); document.write( "\n" ); document.write( "so the third integer is x+4 = 21.
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