document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460043>Question 460043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Andrew factored the expression 28x³-6x²-10x as 2x(14x³-3x²-5x). But when Melissa applied the distributive law and multiplied out 2x(14x³-3x²-5x), she got 28x&#8308;-6x³-10x²; thus, Andrew’s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315586 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When you factor out 2x, divide all the original terms by 2x, not 2.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 28x^3 - 6x^2 - 10x = 2x(14x^2 - 3x - 5)\"> </SPAN>\n" );
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