document.write( "Question 460093: solve using the square root property. 3(x+9)^2-81=0 \n" ); document.write( "
Algebra.Com's Answer #315563 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B9%29%5E2-81=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B9%29%5E2=0%2B81\"Add \"81\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B9%29%5E2=81\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B9%29%5E2=%2881%29%2F%283%29\" Divide both sides by \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B9%29%5E2=27\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B9=%22%22%2B-sqrt%2827%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B9=sqrt%2827%29\" or \"x%2B9=-sqrt%2827%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B9=3%2Asqrt%283%29\" or \"x%2B9=-3%2Asqrt%283%29\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "\"x=-9%2B3%2Asqrt%283%29\" or \"x=-9-3%2Asqrt%283%29\" Subtract \"9\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=-9%2B3%2Asqrt%283%29\" or \"x=-9-3%2Asqrt%283%29\".
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