document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=460085>Question 460085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain sum is doubled in 50 years by simple interest. At the same rate in which time the sum is doubled by compound interest?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315556 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A certain sum is doubled in 50 years by simple interest. At the same rate in which time the sum is doubled by compound interest?  \r<BR>\n" );
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document.write( "Let i = the interest rate in %\r<BR>\n" );
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document.write( "To double certain sum, total interst should be 100\r<BR>\n" );
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document.write( "50*i = 100<BR>\n" );
document.write( "   i = 2\r<BR>\n" );
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document.write( "If 2% interest is compounded annually, the equation becomes<BR>\n" );
document.write( " (1.02)^x = 2\r<BR>\n" );
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document.write( "Log both sides to get\r<BR>\n" );
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document.write( "Log (1.02)^x = log 2<BR>\n" );
document.write( "x Log 1.02 = Log 2<BR>\n" );
document.write( "x = Log 2 / Log 1.02<BR>\n" );
document.write( "x = 35\r<BR>\n" );
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document.write( "At the same rate, the sum is doubled by compound interest in 35 years.  <BR>\n" );
document.write( " </SPAN>\n" );
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