document.write( "Question 47762: slove\r
\n" ); document.write( "\n" ); document.write( "log6 4x-log6 (x-3)=log6 12
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Algebra.Com's Answer #31554 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log6 4x-log6 (x-3)=log6 12
\n" ); document.write( "Keep in mind the base is 6:\r
\n" ); document.write( "\n" ); document.write( "=log(4x/(x-3)) = log12\r
\n" ); document.write( "\n" ); document.write( "Take the anti-log of both sides to get:\r
\n" ); document.write( "\n" ); document.write( "(4x/(x-3)) = 12
\n" ); document.write( "4x=12(x-3)
\n" ); document.write( "4x=12x-36
\n" ); document.write( "8x=36
\n" ); document.write( "x=9/2
\n" ); document.write( "Notice that the base 6 made no difference.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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