document.write( "Question 460032: Hello. Referred to me by Minka.\r
\n" ); document.write( "\n" ); document.write( "The polynomial 0.0013x^3 - 0.075x^2 + 1.5x + 11 models natural gas consumption in trillions of cubic feet, where x=0 corresponds to 1960, x=1 to 1961, and so on.
\n" ); document.write( "In which year between 1970 and 1990 was natural gas consumption about 23.1 trillion cubic feet?\r
\n" ); document.write( "\n" ); document.write( "Truly greatful to whom replies.
\n" ); document.write( "Samantha\r
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Algebra.Com's Answer #315525 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"0.0013x%5E3+-+0.075x%5E2+%2B+1.5x+%2B+11=23.1\"\r
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\n" ); document.write( "\n" ); document.write( " \"0.0013x%5E3+-+0.075x%5E2+%2B+1.5x+=23.1-11\"\r
\n" ); document.write( "\n" ); document.write( "\"0.0013x%5E3+-+0.075x%5E2+%2B+1.5x+=12.1\"\r
\n" ); document.write( "\n" ); document.write( "\"0.0013x%5E3+-+0.075x%5E2+%2B+1.5x+-12.1=0\"\r
\n" ); document.write( "\n" ); document.write( "let's see the graph first:\r
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\n" ); document.write( "\n" ); document.write( "from the graph you see that only \"x=29\" is a real solution that might work\r
\n" ); document.write( "\n" ); document.write( "let's check it:\r
\n" ); document.write( "\n" ); document.write( "\"0.0013x%5E3+-+0.075x%5E2+%2B+1.5x+%2B+11=23.1\"\r
\n" ); document.write( "\n" ); document.write( "\"0.0013%2829%29%5E3+-+0.075%2829%29%5E2+%2B+1.5%2A29+%2B+11=23.1\"\r
\n" ); document.write( "\n" ); document.write( "\"0.0013%2824389%29+-+0.075%28841%29+%2B+1.5%2A29+%2B+11=23.1\"\r
\n" ); document.write( "\n" ); document.write( "\"31.7057+-63.075+%2B+43.5+%2B+11=23.1\"\r
\n" ); document.write( "\n" ); document.write( "\"86.2057+-63.075+=23.1\"\r
\n" ); document.write( "\n" ); document.write( "\"23.1307+=23.1\"\r
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\n" ); document.write( "\n" ); document.write( "if \"x=0+\"corresponds to \"1960\" then \"x=29\" corresponds to \"1989\"\r
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