document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=459983>Question 459983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two friends leave 4.4 mi apart along the same road. if they walk toward eachother at rates that differ by 1/2 mph and meet 48 min later, how fast is each person walking? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315469 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+x+.5=4.4<BR>\n" );
document.write( "2x=3.9<BR>\n" );
document.write( "x=1.95<BR>\n" );
document.write( "x+.5=2.45<BR>\n" );
document.write( "both in 48 minutes<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "1.95/0.8=2.44 mph<BR>\n" );
document.write( "2.45/0.8=3 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );