document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47755>Question 47755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> express in exponential form: log squared 1/8=-3<BR>\n" );
document.write( "sorry that i couldnt find the squared symbol so i just wrote it in.  thanks and i hope you can help me with this question<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31546 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log squared 1/8=-3\r<BR>\n" );
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document.write( "\"log squared\" sound mighty peculiar.<BR>\n" );
document.write( "Are you sure it's not (base 2)<BR>\n" );
document.write( "or maybe the (1/8) is squared.\r<BR>\n" );
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document.write( "I think it is probably base2.<BR>\n" );
document.write( "Assuming it is the problem goes like this:\r<BR>\n" );
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document.write( "log(base2)(1/8)=-3<BR>\n" );
document.write( "2^(-3)=1/8<BR>\n" );
document.write( "2^(-3)=2^(-3)\r<BR>\n" );
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document.write( "A mysterious problem.  I suggest you check it out again.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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