document.write( "Question 459887: A train covers a distance in 50 mins,if it runs at at the speed of 36km/hour on the avarage.The speed at which the trin must run into reduce the time of journey to 30 mins,will be?
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Algebra.Com's Answer #315453 by ankor@dixie-net.com(22740)\"\" \"About 
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A train covers a distance in 50 mins, if it runs at at the speed of 36km/hour on the average.
\n" ); document.write( "The speed at which the train must run into, reduce the time of journey to 30 mins, will be?
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\n" ); document.write( "Let s = speed required to reduce speed to 30 min
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\n" ); document.write( "Time varies inversely to speed, there for
\n" ); document.write( "\"30%2F50\" = \"36%2Fx\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "30x = 50*36
\n" ); document.write( "30x = 1800
\n" ); document.write( "x = \"1800%2F30\"
\n" ); document.write( "x = 60 mph to reduce the time to 30 min
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\n" ); document.write( "Check this out using the actual distance
\n" ); document.write( "dist = 36*\"50%2F60\"
\n" ); document.write( "dist = 30 mi
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\n" ); document.write( "Time going 60 mph: t = 30/60 = .5 hr which is 30 min
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