document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47756>Question 47756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify: 2log(base4)9 - log(base2)3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31545 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2log(base4)9 - log(base2)3\r<BR>\n" );
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document.write( "Note: The exponent of 9 when you use base 4 is (1/2) the exponent of <BR>\n" );
document.write( "9 when you use base 2. <BR>\n" );
document.write( "log(base4)9 = (1/2)log(base2)9<BR>\n" );
document.write( "=2(1/2)log(base2)9 -log(base2)3<BR>\n" );
document.write( "=log(base2)9 - log(base2)3<BR>\n" );
document.write( "=log(base2)(9/3)<BR>\n" );
document.write( "=log(base2)3\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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