document.write( "Question 459943: I'm 46 yrs old and am trying to refresh algebra.\r
\n" ); document.write( "\n" ); document.write( "When the digits of a 2-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?
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Algebra.Com's Answer #315426 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Tlet’s two -digits number be: \"xy\"\r
\n" ); document.write( "\n" ); document.write( "\"x+\"= the 10's digit
\n" ); document.write( "\"y+\"= units digit\r
\n" ); document.write( "\n" ); document.write( "The original number is: \"10x+%2B+y\"\r
\n" ); document.write( "\n" ); document.write( "given: \r
\n" ); document.write( "\n" ); document.write( "the digits of a two-digit number are reversed, the new number is \"9\"\"+more\"
\n" ); document.write( " than the original number\r
\n" ); document.write( "\n" ); document.write( "the sum of the digits of the original number is 11: \"x+%2B+y+=+11\".....\r
\n" ); document.write( "\n" ); document.write( "you will have:\r
\n" ); document.write( "\n" ); document.write( "\"10y+%2B+x+=+10x+%2B+y+%2B+9\"\r
\n" ); document.write( "\n" ); document.write( "\"10y+-+y+=+10x+-+x+%2B+9\"\r
\n" ); document.write( "\n" ); document.write( "\"9y+=+9x+%2B+9\".........both sides divide by \"9\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+x+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "Replace \"y+\"with \"%28x%2B1%29\" and plug it in \"x+%2B+y+=+11\"\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+x+%2B+1+=+11\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+=+10\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+5\"......the 10's digit\r
\n" ); document.write( "\n" ); document.write( "then, the units digit will be\r
\n" ); document.write( "\n" ); document.write( "\"y+=+5+%2B+1\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+6\"\r
\n" ); document.write( "\n" ); document.write( "and the original number is: \"10x+%2B+y=10%2A5%2B6=56\"\r
\n" ); document.write( "\n" ); document.write( "if the digits of a two-digit number are reversed, we will have a number \"65\"\r
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\n" ); document.write( "\n" ); document.write( "\"65-56=9\"...so, the new number is \"9\"\"+more\"
\n" ); document.write( " than the original number
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