document.write( "Question 459926: What are the steps to simplify this problem?\r
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document.write( "logc20c/logc50-logc5\r
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document.write( "(log in base c 20c divided by log base c 50 minus log base c 5) \n" );
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Algebra.Com's Answer #315413 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! logc(20c)/logc50-logc5 \n" ); document.write( "---- \n" ); document.write( "= {[logc(20)-logc(c)]/logc(50)}- logc(5) \n" ); document.write( "----- \n" ); document.write( "= {[logc(20)-1]/logc(50)} - logc(5) \n" ); document.write( "========================================== \n" ); document.write( "If your problem is really the following you get a different answer:\r \n" ); document.write( "\n" ); document.write( "logc(20c)/[logc50-logc5] \n" ); document.write( "--- \n" ); document.write( "= [logc(20)-1]/[logc(50/5)] \n" ); document.write( "--- \n" ); document.write( "= [logc(20)-1]/[logc(10)] \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |