document.write( "Question 459926: What are the steps to simplify this problem?\r
\n" ); document.write( "\n" ); document.write( "logc20c/logc50-logc5\r
\n" ); document.write( "\n" ); document.write( "(log in base c 20c divided by log base c 50 minus log base c 5)
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Algebra.Com's Answer #315413 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
logc(20c)/logc50-logc5
\n" ); document.write( "----
\n" ); document.write( "= {[logc(20)-logc(c)]/logc(50)}- logc(5)
\n" ); document.write( "-----
\n" ); document.write( "= {[logc(20)-1]/logc(50)} - logc(5)
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\n" ); document.write( "If your problem is really the following you get a different answer:\r
\n" ); document.write( "\n" ); document.write( "logc(20c)/[logc50-logc5]
\n" ); document.write( "---
\n" ); document.write( "= [logc(20)-1]/[logc(50/5)]
\n" ); document.write( "---
\n" ); document.write( "= [logc(20)-1]/[logc(10)]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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