document.write( "Question 459921: the length of a rectangle is 4ft longer than its width. If the perimeter of the rectangle is 44ft, find its area. \n" ); document.write( "
Algebra.Com's Answer #315411 by nerdybill(7384)\"\" \"About 
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the length of a rectangle is 4ft longer than its width. If the perimeter of the rectangle is 44ft, find its area.
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\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "w+4 = length
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\n" ); document.write( "2(w + w+4) = 44
\n" ); document.write( "w + w+4 = 22
\n" ); document.write( "2w+4 = 22
\n" ); document.write( "2w = 18
\n" ); document.write( "w = 9 feet (width)
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\n" ); document.write( "Length:
\n" ); document.write( "w+4 = 9+4 = 13 feet
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\n" ); document.write( "Area:
\n" ); document.write( "9 * 13 = 117 square feet\r
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