document.write( "Question 459891: 9+3b+(3a-b)i=6+6i\r
\n" ); document.write( "\n" ); document.write( "I'm thinking of this question for 1 hour, and i can't find the answer, can u please help me\r
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Algebra.Com's Answer #315391 by sudhanshu_kmr(1152)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "9+3b+(3a-b)i=6+6i (separate real and imaginary values also separate variable on left side and constants on right side.)\r
\n" ); document.write( "\n" ); document.write( "=> 3b + (3a-b)i = 6 + 6i -9 \r
\n" ); document.write( "\n" ); document.write( "=> 3b + (3a-b)i = -3 + 6i \r
\n" ); document.write( "\n" ); document.write( "now compare real and imaginary values..\r
\n" ); document.write( "\n" ); document.write( "i.e 3b = -3 \r
\n" ); document.write( "\n" ); document.write( " and 3a-b = 6\r
\n" ); document.write( "\n" ); document.write( "from first equation b = -1 now, put this value on second \r
\n" ); document.write( "\n" ); document.write( "3a+1 = 6 \r
\n" ); document.write( "\n" ); document.write( "=> a = 5/3 \r
\n" ); document.write( "\n" ); document.write( "so, a= 5/3, b = -1 \r
\n" ); document.write( "\n" ); document.write( "if any doubt, you are welcome to contact me..
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