document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47720>Question 47720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of theline that contains the point (5,-7) and perpendicular to y=1/2x-4\r<BR>\n" );
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document.write( "Thank you, Michelle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31537 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find an equation of theline that contains the point (5,-7) and perpendicular to y=1/2x-4..........................1<BR>\n" );
document.write( "EQN.OF LINE PERPENDICULAR TO 1 IS <BR>\n" );
document.write( "Y=-2X+K.........FOR PERPENDICULAR LINES PRODUCT OF SLOPES SHOULD BE -1..SO IF M1=1/2...M2=-2...SO THAT M1M2=-1<BR>\n" );
document.write( "THIS PASSES THROUGH 5,-7...SO<BR>\n" );
document.write( "-7=-2*5+K=-10+K<BR>\n" );
document.write( "K=10-7=3<BR>\n" );
document.write( "HENCE EQN. OF LINE IS <BR>\n" );
document.write( "Y=3-2X \r<BR>\n" );
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document.write( "Thank you, Michelle </SPAN>\n" );
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